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1.Units, Dimensions and Measurement
medium
A certain body weighs $22.42\;g$ and has a measured volume of $4.7 \;cc .$ The possible error in the measurement of mass and volume are $0.01\; gm$ and $0.1 \;cc .$
Then maximum error in the density will be
A$22$
B$0.2$
C$2$
D$0.02$
(AIPMT-1991)
Solution
$\frac{\Delta \rho}{\rho}=\left[\frac{\Delta m}{m}+\frac{\Delta V}{V}\right] \times 100 \%$
$\frac{\Delta \rho}{\rho}=\left[\frac{0.01}{22.42}+\frac{0.1}{4.7}\right] \times 100 \%$
$\frac{\Delta \rho}{\rho}=2 \%$
$\frac{\Delta \rho}{\rho}=\left[\frac{0.01}{22.42}+\frac{0.1}{4.7}\right] \times 100 \%$
$\frac{\Delta \rho}{\rho}=2 \%$
Standard 11
Physics
